A plane flies from Springville to Brockton and then back to Springville. When there is no wind, the round trip takes 6 hours and 24 minutes, but when there is a wind blowing from Springville to Brockton at 50 miles per hour, the trip takes 6 hours and 40 minutes. How many miles is the distance from Springville to Brockton?

Step-by-step explanation:

Let x represent the speed of the plane in still air.

When there is no wind, the round trip takes 6 hours and 24 minutes. Converting to hours, it becomes

6 + 24/60 = 6 + 0.4 = 6.4 hours

Distance = speed × time

Distance of the round trip = 6.4x

But when there is a wind blowing from Springville to Brockton at 50 miles per hour, the trip takes 6 hours and 40 minutes. Converting 6 hours and 40 minutes, it becomes

6 + 40/60 = 6 2/3 = 20/3 hours

The total speed would be

(x - 50)miles per hour

Distance covered = 20/3(x - 50)

Therefore, since both round trips are the same distance, then,

6.4x = 20/3(x - 50)

Cross multiplying by 3, it becomes

19.2x = 20(x - 50)

19.2x = 20x - 1000

20x - 19.2x = 1000

0.8x = 1000

x = 1000/0.8 = 1250 mph

Distance covered on the round trip is

6.4x = 6 × 1250 = 7500 miles

Therefore, the distance from Springville to Brockton is

7500/2 = 3750 miles

225 in²

Step-by-step explanation:

First you have to find the ∛3,375 since it is a cube you know that all the dimensions are the same so when 15 comes out all you have to do is multiply the height by the length to get the area of one of its sides to get the answer.