Mathematics: a plane intersects a cylinder parallel to the cylinder’s bases. what’s the area of the resulting cross section? use 3.14 for π. round your answer to the nearest tenth

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a plane intersects a cylinder parallel to the

reneebrown017

03.01.2022

The area of the resulting cross section is $78.5\ m^{2}$

Step-by-step explanation:

we know that

The resulting cross section is a circle congruent with the circle of the base of cylinder

therefore

The area is equal to

$A=\pi r^{2}$

we have

$\pi=3.14$

$r=10/2=5\ m$ -----> the radius is half the diameter

substitute the values

$A=(3.14)(5)^{2}=78.5\ m^{2}$

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