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michellerosas
30.03.2020 •
Mathematics
A plane leaves airport A and travels 570 miles to airport B on a bearing of Upper N 32 degrees Upper E. The plane later leaves airport B and travels to airport C 390 miles away on a bearing of Upper S 73 degrees Upper E. Find the distance from airport A to airport C to the nearest tenth of a mile.
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Ответ:
769.46 miles
Step-by-step explanation:
Please have a look at the photo attached in this answer
The missing part of the angle is 32 degrees, so the total angle of B is:
32 + 73 = 105 degrees.
Let x is the distance from airport A to airport C to the nearest tenth of a mile, we use cosine law to find x:
<=>
= 592070
<=> x =
= 769.46 miles
Ответ:
121 square feet
Step-by-step explanation:
The area of a triangle is the height multiplied by the base divided by 2. Since this is a right triangle, you can simply use the two legs for this. The area of this triangle is therefore:
Hope this helps!