A polynomial function is described. Find all remaining zeros. Degree: 6 with zeros of -1, multiplicity of 2, 1–3i, and 2 + 5i.
-
A
1 + 3i and 2 - 5i
B
-1-3i and -2 + 5i
C
3i and -5i
D
-1 + 3i and -2 – 5i

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Ответ:

viridianasar5158

22.10.2020

Mathematics

So the answer is DNC(Does Not Convergence)

Step-by-step explanation:

Given;

$\int\limits^\infty_5 {\frac{7}{x^{2}-9 } } \ dx$

We know,

The integral is an improper integral because the upper limit of integration approaches infinity. First, replace the infinite upper limit by the finite limit 'l' and take the limit of 'l' to approach infinity.

$\int\limits^\infty_5 {\frac{7}{x^{2}-9 } } \, dx=7 \lim_{l \to \infty} \int\limits^\infty_5 {\frac{1}{x^{2}-9 } } \, dx$

$7 \lim_{l \to \infty} \int\limits^\infty_5 {\frac{1}{x^{2}-3^{2} } } \, dx$

$7\times \lim_{l \to \infty} \left [ \frac{1}{2\times 3} \log\left |\frac{x-3}{x+3} \right | \right ]_{5}^{l}$ (∵We know; $\int {\frac{1}{x^{2}-a^{2} } } \, dx= \frac{1}{2\times a} \log\left |\frac{x-3}{x+3} \right |$ )

$\frac{7}{6} \times \lim_{l \to \infty} \left[ \log\left | \frac{l-3}{l+3} \right |-\log\left | \frac{5-3}{5+3}\right |\right]$

$\frac{7}{6} \times \lim_{l \to \infty} \left[ \log\left | \frac{l-3}{l+3} \right |-\log\left | \frac{-2}{8}\right |\right]$

$\frac{7}{6} \times \left[ \log\left | \frac{\infty-3}{\infty+3} \right |-\log( \frac{2}{8})\right]$ (∵ $\left | -\frac{2}{8} \right |=(\frac{2}{8} )$ )

$\frac{7}{6} \times \left[ \infty-\log( \frac{2}{8})\right]$

$\frac{7}{6}\times \infty$

$\infty$

Thus the integral Does Not Convergence.

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A polynomial function is described. Find all remaining zeros. Degree: 6 with zeros of -1, multiplicity of 2, 1–3i, and 2 + 5i. - A 1 + 3i and 2 - 5i B -1-3i and -2 + 5i C 3i and -5i D -1 + 3i and -2 – 5i