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sbush5231
23.10.2020 •
Mathematics
A quality control inspector has drawn a sample of 18 light bulbs from a recent production lot. If the number of defective bulbs is 1 or more, the lot fails inspection. Suppose 30% of the bulbs in the lot are defective. What is the probability that the lot will fail inspection? Round your answer to four decimal places.
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Ответ:
0.9983
Step-by-step explanation:
Given that :
Number of samples = 18
P(defective bulb) = 30% = 0.3
Inspection failure = defective bulb is 1 or more
Hence, inspection failure occurs if;
P(x ≥ 1) = 1 - P(x < 1)
P(x ≥ 1) = 1 - P(x = 0)
Using the binomial probability function :
nCx * p^x * (1 - p)^(n-x)
p = probability of success per trial ; n = number of trials
n = 18
P(x = 0) = [ 1 - (18C0 * 0.3^0 * (1 - 0.3)^(18-0))
= [1 - (1 * 1 * 0.7^18)]
1 - 0.0016284136
= 0.9983
Ответ:
Step-by-step explanation: