Cooldude497
26.03.2020 •
Mathematics
A rectangle has a height of 4w^3 and a width of 5w^2-3w-4 what is the area
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Ответ:
A = 5w^5 - 3w^4 - 4w^3
Step-by-step explanation:
The area of a rectangle
A = ( l * b)
A - area of a rectangle
l - length/height of a rectangle
b - breadth/ width of a rectangle
Given
h = 4w^3
w = 5w^2 - 3w - 4
A = h * w
A = 4w^3 * 5w^2 - 3w - 4
= 4w^3(5w^2 - 3w - 4)
Hint: 4w^3 * 5w^2 = 20w^5
w^3 * w^2 = w^3+2
= w^5
4w^3 * -3w = -12w^4
w^3 * w = w^3 + 1
= w^4
4w^3 * -4 = -16w^3
Collect the terms
= 20w^5 - 12w^4 - 16w^3
Simply further by dividing through by 2
= 10w^5 - 6w^4 - 8w^3
Simply by dividing through by 2
= 5w^5 - 3w^4 - 4w^3
Ответ:
0.083
Step-by-step explanation: