A rectangle measures 10 feet by 6 feet. The length and width are each increased by 50%. What is the area of the new rectangle? Work shown with it please

One hundred and thirty five

Step-by-step explanation:

fifty percent of ten is five so the new side is fifteen feet. fifty percent of six is three so that new side is nine feet. nine times fifteen is one hundred and thirty five

The new area would be 135 feet. 50% of 10 is 5. so 5+10=15 50% of 6 is 3 so 3+6=9 so do 15 times 9 to get 135!

A) sin 120=sin (180-60)=sin 60= (It lies on second quadrant where sin is +ve)
B)  tan (150)=tan(180-30)=-tan30=(It lies on second quadrant where tan is -ve)
C) cos (-135)=cos (135)=cos (180-45)=-cos (45)=(It lies on second quadrant where cos is -ve)
D) sec (300)=sec (360-60)=sec(60)=2 (It lies on fourth quadrant where sec is +ve)
E) sin (240)=sin(180-(-60))=sin(-60)=-sin (60)=
(It lies on third quadrant where sin is -ve)
 F) cos (330)=cos(360-30)=cos(30)=
(It lies on fourth quadrant where cos is +ve)
sin (240)- cos (330)=