A rectangular auditorium seats 1855 people. The number of seats in each row exceeds the number of rows by 18. Find the number of seats in each row.

53 seats per row

Step-by-step explanation:

Given that:

Capacity = 1855

Let number of rows = x

Hence, Number of seats per row = x + 18

The Area of auditorium = capacity

Area of rectangle = Length * width

1855 = x * (x + 18)

1855 = x² + 18x

x² + 18x - 1855 = 0

x² + 53x - 35x - 1855 = 0

x(x + 53) - 35(x + 53) = 0

(x - 35) = 0 or (x +53) = 0

x = 35 or x = - 53

Hence x = 35 ; (x can't be negative)

Number of seats per row = 35 + 18 = 53

Using a quadratic equation cal

Step-by-step explanation:

Moon: 100:16.5 = 60:x

100x = 16.5*60

x=9.9

Mars: 100:38=60:x

100x=38*60

x=22.8