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ahankaranth
04.02.2020 •
Mathematics
"a rectangular painting measures 12 inches by 16 inches and is surrounded by a frame of uniform width around the four edges. the perimeter of the rectangle formed by the painting and its frame is 72 inches. determine the width of the frame.\"
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Ответ:
Data:
lenght=16 in.
width=12 in.
Area (rectangular painting)=16 in * 12 in=192 in².
x=width of the frame.
lenght of the frame=16+2x
width of the frame=12+2x
Perimeter of the painting and its frame=2(16+2x)+2(12+2x)
We can suggest this equation:
2(16+2x)+2(12+2x)=72
32+4x+24+4x=72
4x+4x=72-32-24
8x=16
x=16/8
x=2
the width of the frame is 2 in.
Ответ:
w= -16