Mathematics: A rectangular wading pool measures 7 feet by 6 feet by 2.5 feet. When the pool is empty, it weighs 35 pounds. If water weighs 6.24 pounds per cubic foot, what is the total weight of the pool when it is full of water?

The correct answer would be B because you have to add all of the a’s b’s and c’s together and then add them together!...

A rectangular wading pool measures 7 feet by 6 feet

Ответ:

jahnoibenjamin

01.02.2022

Mathematics

The total weight of the pool when it is full of water is 690.2 pounds.

Step-by-step explanation:

We know that total weight of the wading pool ( $m_{T}$ ) is the sum of the weight of empty pool ( $m_{pool}$ ) and the weight of water ( $m_{w}$ ), all measured in pounds, that is:

$m_{T} = m_{pool} + m_{w}$

The weight of water can be determined by definition of density, as we know the geometry of the wading pool and density of water:

$m_{w}=\rho_{w}\cdot (w\cdot h\cdot l)$

Where:

$\rho_{w}$ - Density, measured in pounds per cubic foot.

, , - Width, height and length of the wading pool, measured in feet.

Now, we are noticed that $\rho_{w} = 6.24\,\frac{pd}{ft^{3}}$ , $w = 7\,ft$ , $h = 6\,ft$ , $l = 2.5\,ft$ and $m_{pool} = 35\,pd$ and the total weight of the pool when it is full of water is: