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prudencerufus
31.12.2020 •
Mathematics
A rental car company claims the mean time to rent a car on their website is 60 seconds with a standard deviation of 22 seconds. A random sample 36 customers attempted to rent a car on the website. The mean time to rent was 55 seconds. Is this enough evidence to say that the mean time is less than the company's claim? Consider α=0.05.
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Ответ:
Since the calculated value of Z does not fall in the critical region we accept our null hypothesis that mean = 60 seconds
Step-by-step explanation:
State the null hypothesis
H0: u = 60against the claim
Ha u≠ 60 (this is a two tailed test)
Sample size n= 36
Sample mean=X`= 55
Population mean = u= 60
The significance level α = 0.05
Standard deviation= Sd = 22 seconds
Z= X`- u / Sd /√n
Z= 55- 60 / 22/√6
z= - 5/22/6
Z= -1.3635
The value of z from the table is Z∝/2= ±1.96
The critical region is less than - 1.96 and greater than 1.96.
Since the calculated value of Z does not fall in the critical region we accept our null hypothesis that mean = 60 seconds
Ответ:
the complex number and its additive inverse should equal 0 + 0i