kat1357
11.05.2021 •
Mathematics
A report from 2015 claims that the average salary of a server is $12 per hour. You collect data from a random sample of 30 servers in Atlanta and calculate the average salary for servers from your sample to be $11.00 with a standard deviation of $2.80. Conduct a hypothesis test to determine if the true average hourly wage of a server is different than the claim of $12.
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Ответ:
Since the calculated value z= -1.956 does not lie in the critical region z= ± 1.96 we conclude that true average hourly wage of a server is not different than the claim of $12.
Step-by-step explanation:
The null and alternate hypotheses are
H0: u= 12 against the claim Ha: u≠ 12
Taking significance level alpha = 0.05
The critical region is z= ± 1.96 for two tailed test
The sample size = n= 30
The sample mean = 11
Sample standard deviation= 2.80
Applying z- test
Z= x-u/s/√n
z= 11-12/2.8/√30
z= -1/0.5112
z= -1.956
Since the calculated value z= -1.956 does not lie in the critical region z= ± 1.96 we conclude that true average hourly wage of a server is not different than the claim of $12.
Ответ:
Step-by-step explanation:
So, to start, we need to label all the values. This is
16, 17, 17, 17, 18, 18 , 18 , 18, 18, 18, 19, 19, and 20.
The Lower Quartile can be found if you know the median. The median in this case is 18. So, the Lower Quartile is just median between the median and the lowest number. So it is the median between 18 and 16. Not average, but the median in the set. In this case it is 17. The Upper Quartile is the same except now it is between the median and highest value, or 18.5. The IQR is found by subtracting the Upper by the Lower, or 18.5-17, or 1.5.