a right triangle has a hypotenuse that is between 28 and 29 units long name 2 pair of lengths that could be the length of the legs of the right triangle PLS HURRY

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Ответ:

aliviafrancois2000

21.09.2021

Mathematics

Hence, the desired equation is:

$x+6=64+x-16\sqrt{x}$

Step-by-step explanation:

We are given a equation as:

$\sqrt{x+6}+\sqrt{x}=8$

We can also write this equation as i.e. we can isolate our radical term as:

$\sqrt{x+6}=8-\sqrt{x}$

Now on squaring both side of the equation we get:

$(\sqrt{x+2})^{2}=(8-\sqrt{x})^2$

We know that:

(a-b)^2=a^2+b^2-2ab

so, we get from the equation:

$x+6=8^2+(\sqrt{x})^2-2\times 8\times \sqrt{x}\\\\x+6=64+x-16\sqrt{x}$

Hence, the desired equation which is obtained as a result from isolating a radical term and squaring both sides of the equation for the equation is:

$x+6=64+x-16\sqrt{x}$

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