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Abrahamolve
30.10.2020 •
Mathematics
A road rises 1 m for every 15 m measured along the road. a) What is the angle of inclination of the road to the nearest degree? b) How far does the car travel horizontally when it travels 15 m along the road ? Give the answer to the nearest tenth of a metre.
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Ответ:
The answer is below
Step-by-step explanation:
The road increases by a height of 1 m for every 15 m distance. The slope of a line is the ratio of its rise to run. The slope (m) is the tangent of the inclination. Hence:
Slope = rise / run = tanθ
Where θ is the angle of inclination.
a) Given rise = 1 m, run = 15 m
Slope of road (m) = rise / run
m = 1 m/ 15 m
m = 0.0667
slope = tanθ
tanθ = 0.0667
θ = tan⁻¹(0.0667)
θ = 3.81
θ ≈ 4°
b) cosθ = horizontal distance / 15 m
horizontal distance = 15 m × cos 4
Horizontal distance = 14.96
Horizontal distance = 15 m to nearest tenth
Ответ:
3x = 95 -7
3x = 88
X = 88/3
Or if you mean 95° is the total angles except A
180-95=85
3x +7= 85
3x = 85-7
3x = 78
X = 26