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Gloryreak3728
03.09.2020 •
Mathematics
A rocket is launched at 19.6 m/sec. from a 58.8 meter tall platform.
The equation for height of the rocket’s height, s, at time, t, seconds after launch
Is represented by s(t)= -16t^2+19.6t+58.8 where s is in meters. When does the rocket hit the ground assuming the ground is at sea level?
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Ответ:
i am back;-;
Step-by-step explanation:
the answer is b btw