A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the
time that the rocket will hit the ground, to the nearest 100th of second.
y = –16x2 + 119x + 57

7.89 seconds

Step-by-step explanation:

using the quadratic formula (-b+-√(b^2-4ac))/2a

a=-16 b=119 c=57

x=-0.451

and

x=7.889

time cant be negative so use the positive x

  f(x) = (4/5)√x

Step-by-step explanation:

Since the rented area is square, the length of it is the square root of x. 4/5 of that is the length of one row of shelves, so is ...

  f(x) = (4/5)√x