A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second. -16x^2+129x+119

8.90 seconds

Step-by-step explanation:

When the rocket hits the ground, its height ( y ) will be zero. This means we can write the equation as:

So we need to solve that equation:

x₁ = -0.84

x₂ = 8.90

We discard x₁, as it is negative.

So the answer is x₂, 8.90 seconds.

x=0,1/2,-3,3

Step-by-step explanation:

first factor out an x and we are left with x(2x^3-x^2-18x+9)

we can then factor out (2x-1) and we are left with x^2-9

This now becomes x-3(x+3)

finally we have x(2x-1)(x-3)(x+3)

Now just set each one to 0 and solve for x