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dianereyes7475
07.04.2020 •
Mathematics
A sample of 100 clients of an exercise facility was selected. Let X = the number of days per week that a randomly selected client uses the exercise facility. X Frequency 0 3 1 15 2 31 3 27 4 10 5 7 6 7 Find the number that is 1.5 standard deviations BELOW the mean. (Round your answer to three decimal places.)
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Ответ:
-5.053
Step-by-step explanation:
For complete calculation see the attachment:
mean= (0 +3+1+15+2+31+3+27+4+10+5+7+6+7)/14= 8.6429 or 9 days
standard deviation= √(∑(X-mean)²/N)
9.1309 or 9 days
1.5 standard deviation= 9.1309× 1.5= 13.6963
number 1.5 standard deviation below the mean= 8.6429-13.7= -5.053
Ответ:
y= .5x+15
see attached graph
They are charging $.50 per mile. That is the slope.
The y intercept in the flat fee or $15
Step-by-step explanation:
Let x be the number of miles driven
Let y be the total cost for the day.
They are charging $.50 per mile. That is the slope.
This is the change in y over the change in x (.5/1) Go up .5 and to the right 1.
The y intercept in the flat fee or $15
This is the point where it crosses the y axis (x= 0)
We can write this in the form
y= mx+b
y= .5x+15