A sample of 14001400 computer chips revealed that 311% of the chips do not fail in the first 10001000 hours of their use. The company's promotional literature claimed that more than 28(% do not fail in the first 10001000 hours of their use. Is there sufficient evidence at the 0.050.05 level to support the company's claim

There is sufficient evidence at 0.05 significant level to support company's claim.

Step-by-step explanation:

We have these informations from the question

n = 1400

P^ = 31% = 0.31

Alpha level = 5% = 0.05

Then we come up with the hypothesis

H0: P = 0.28

H1: P>0.28

From here we calculate the test statistic

z = p^ - p/√pq/n

P = 0.28

q = 1-0.28

= 0.72

z = 0.31-0.28/√(0.31*0.72)/1400

= 0.03/√0.0001594

= 0.03/0.012

= 2.5

Then we have a p value = 0.00621

The p value is less than significance level

0.00621<0.05

So the null hypothesis is rejected.

We conclude that There is sufficient evidence at 0.05 significant level to support company's claim.

$151.34

Step-by-step explanation:

You would do 138.72 minus 45.23.

138.72 minus 45.23 is 93.49.

Then, you would do 93.49 minus 18.

93.49 minus 18 is 75.49.

Now, you would add 75.49 and 75.85 together to get the answer.

75.49 + 75.85 = 151.34