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cbaughn11
26.05.2021 •
Mathematics
A sample of 169 observations showed an average of 15 and a standard deviation of 26. Construct the 88% confidence interval for the population mean. What is the upper limit of this interval
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Ответ:
18.11
Step-by-step explanation:
The formula for Confidence Interval is given as:
Confidence Interval = μ ± z × σ /√n
μ = the population mean/average = 15
σ = the population standard deviation = 26
z = z score of 88% confidence interval = 1.5548
= 15 ± 1.5548× 26/√169
= 15 ± 1.5548 × 26/13
= 15 ± 1.5548 × 2
= 15 ± 3.11
Hence,
Confidence Interval = 15 ± 3.11
Lower Limit
= 15 - 3.11
= 11.89
Upper limit
= 15 + 3.11
= 18.11
Therefore, the upper limit of the 88% confidence interval is 18.11
Ответ:
−√33/7
Step-by-step explanation:
Second quadrant implies cos negative, as cos is projection from
unit circle to x axis.
sin^2+cos^2=1
cos= sqrt(1-sin^2)
sin^2 = 16/49
1-sin^2 = 33/49
sin= -sqrt(33)/7