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quanharris2k19
24.07.2021 •
Mathematics
A sample of 500 nursing applications included 60 from menThe 95% confidence interval of the true proportion of men who applied to the nursing program is
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Ответ:
The correct solution is "(0.092, 0.148)".
Step-by-step explanation:
Given:
Sample size,
n = 500
True proportion,
The standard error will be:
The confidence interval is "1.96".
hence,
The required confidence interval will be:
=![(\hat p - 1.96 SE, \hat p + 1.96 SE)](/tpl/images/1398/8842/9272d.png)
By substituting the values, we get
=![(0.12-1.96\sqrt{\frac{0.12(0.88)}{500} }, 0.12+1.96\sqrt{\frac{0.12(0.88)}{500} } )](/tpl/images/1398/8842/a9595.png)
=![(0.092, 0.148)](/tpl/images/1398/8842/5776b.png)
Ответ:
The area of the rectangle would be (11)(7) =77
The area of the square is (6)(6)=36
77+36=113
Hope this helped :)