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oscargonzalez1991
04.07.2020 •
Mathematics
A sandwich shop is ordering apples and grapes to make chicken salad. Apples cost $2.19 per pound and grapes cost $2.60 per pound. If they ordered a total of 20 pounds of apples and grapes and paid $35.80, how many pounds of grapes did they order? We got $19.51 but we think it is wrong.
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Ответ:
Less than 13 pounds of grapes,
as 14 pounds of grape exceeds $35.80,
If you order as low as zero pounds of grapes, then the price of apple pounds would be $35.80/20 =$1.79 per pound
Step-by-step explanation:
Let
Quantity of Apple and grapes=20
Cost of apple=$2.19
Cost of grape=$2.60
Total cost of apple and grape=$35.80
a+g=20
a=20-g
PaQa+PgQg=35.80
2.19(20-g)+2.60g=35.80
43.8-2.19g+2.60g=35.80
0.41g=35.80-43.8
0.41g=-8
g=-8/0.41
g= -19.51
PaQa+PgQg=35.80
2.19a+2.60(-19.51)=35.80
2.19a-50.726=35.80
2.19a=35.80+50.726
2.19a=86.526
a=86.526/2.19
=39.51
PaA+PgG=35.80
Pa(20-G)+2.60G=35.80
35.80/2.60 = 13.77 pounds of grapes, but no money will be left to buy apples, unless Pa=0
G<13.77
Ответ:
3x = 95 -7
3x = 88
X = 88/3
Or if you mean 95° is the total angles except A
180-95=85
3x +7= 85
3x = 85-7
3x = 78
X = 26