A school bus has 23
seats that will fit 3
students each and
one seat that will fit 2
students. How many
students will fit on
the bus?

1) the probability that the proportion of vegetarians in the sample would be greater than 9% is 0.1902

2) the probability that the mean of the sample would differ from the population mean by less than 1.1 points in the is 0.3616

p( /x" - u/ < 0.47 ) = 0.3616

Step-by-step explanation:

1)

Given that;

p = 8% = 0.08 and n = 569

what is the probability that the proportion of vegetarians in a sample of 569 Americans would be greater than 9% (0.09)

that is;

p( p" > 0.09) = ?

p( p" > 0.09) = p( z > [(0.09 - 0.08)/(√((0.08(1 - 0.08))/569))] )

= p( z > (0.01 / 0.0114))

= p ( z > 0.8772)

= 0.1902

Therefore the probability that the proportion of vegetarians in the sample would be greater than 9% is 0.1902

2)

Given that;

mean points obtained in an aptitude examination u = 166

standard deviation α = 19

sample size n = 66

x" - u = 1.1

first we say

x-score = (x" - u) / (α/√n) = 1.1 / (19/√66) = 1.1 / 2.3387 = 0.47

p( -0.47 < z < 0.47 )

= p( z < 0.47) - p( z < - 0.47)

= 0.6808 - 0.3192

= 0.3616

Therefore the probability that the mean of the sample would differ from the population mean by less than 1.1 points in the is 0.3616

p( /x" - u/ < 0.47 ) = 0.3616