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skyrileycasting
27.06.2020 •
Mathematics
A semicircular plate with radius 8 m is submerged vertically in water so that the top is 3 m above the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s2 for the acceleration due to gravity. Recall that the weight density of water is 1000 kg/m3.)
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Ответ:
If the square end is under water: 312271.92 N
If the round end is under water: 262976.67 N
Step-by-step explanation:
We have to:
P = ρ·g·d
where:
P is hydrostatic pressure, g is gravitational acceleration, d is depth, ρ is fluid density
Force = hydrostatic pressure x submerged area
F = PA
You didn't specify the orientation
If the square end is under water:
F = (1000 kg/m³) (9.81 m/s²) (2) ∫ (2-y)√(64 - y²) dy from 0 to 2
F = 19620 ∫ (2-y)√(64 - y²) dy from 0 to 2
The result of the solution of the integral is 15.916
Thus:
F = 15.916*19620 = 312271.92 N
If the round end is under water:
F = (1000 kg/m³) (9.81 m/s²) (2) ∫ (y - 3) √(64- y²) dy from 3 to 5
F = 19620 ∫ (y - 3) √(25 - y²) dy from 3 to 5
The result of the solution of the integral is 13.403
Thus:
= 13.403*19620 = 262976.67 N
Ответ:
A = pi * r^2
= pi * (2x^-3)^2
= pi * 2^2 * (x^-3)^2
= pi * 4 * (x^-6)
= 4*pi * x^-6