shongmadi77
18.03.2020 •
Mathematics
A sequence of steps for solving the equation 3(x-2)=x+4
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Ответ:
Step-by-step explanation:
Step 1 is the given expression.
In Step 2, we have used the distributive property to eliminate parentheses.
In Step 3, -x as been added to both sides.
In Step 4, +6 has been added to both sides.
In Step 5, both sides have been multiplied by 1/2.
If the boxes on the left are identified as A to E from top to bottom, they are filled with the numbers 5, 4, 1, 3, 2 in that order.
Ответ:
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Form- 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalmente factorizada: f (x) = (x - 3) (x + 3) [x - (2 - i)] [x - (2 + i)] La función tiene raíces reales y raíces imaginarias.
Forma totalment