A STADIUM HAS 15,600 SEATS. IT HAS 60 ROWS OF SEATS ALTOGETHER. THE 35 ROWS AT THE BACK HAVE 300 SEATS EACH. THE REST OF THE ROWS AT THE FRONT HAVE THE SAME NUMBER OF EACH SEATS EACH. HOW MANY SEATS ARE THERE IN EACH OF THE ROWS AT THE FRONT

The number of seats in each of the rows at the front =204

Step-by-step explanation:

Let x = The number of seats in each of the rows at the front.

Given: Total seats = 15,600

Total rows = 60

Rows in back = 35

Rows in front = 60-35=25

Total seats in front = 25x

Each row in the back has 300 seats.

Total seats in the back =300 x35=10500

Seats in front = 15600-10500=5100

i.e.

Hence, the number of seats in each of the rows at the front =204

.b. It is one‐half as large as when n = 100.

Step-by-step explanation:

Given that a  simple random sample of 100 batteries is selected from a process that produces batteries with a mean lifetime of 32 hours and a standard deviation of 3 hours.

i.e. s = 0.3

we obtain se of sample by dividing std devitation by the square root of sample size

i.e. s=

when n =100 this = 0.3 and

when n =400 this equals 0.15

We find that when sample size is four times as large as original, std deviation becomes 1/2 of the original

Correction option is

.b. It is one‐half as large as when n = 100.