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wolffee895
04.05.2021 •
Mathematics
A(t)=400e^-0.032(t)
after 3, 8 and 10 yrs
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Ответ:
converge at![I=\frac{1}{3}](/tpl/images/0455/4421/04ee2.png)
Step-by-step explanation:
Given
Improper Integral I is given as
integration of
is -![\frac{1}{x}](/tpl/images/0455/4421/3230f.png)
substituting value
so the value of integral converges at![\frac{1}{3}](/tpl/images/0455/4421/5506e.png)