Mathematics: A taxi cab costs $1.50 for the 1st mile and $0.75 for each additional mile. Which equation could be solved to find how many miles you can travel in a taxi for $10, given that X is the number of additional miles? A. 1.5x +0.75 = 10 B. 0.75x +1.5 = 10 C. 1.5x -0.75 = 10 D. 0.75x -1.5 = 10 Please answer right away worth 15 points!

Step-by-step explanation:the equation is to solve we need to make the equation equal to zero, for that we substract 35 on each side:we have now an equation in the general form: where and we find the values for x with the general formula:substituting known valuessince we had a quadratic equation we will have 2 answers, one taking the positive sign and the other with the negative sign: ≈ 10.916 ≈ -0.916...

A taxi cab costs $1.50 for the 1st mile and $0.75 - id150107511495235, yazmineespinozarive

Ответ:

tommy4260

03.10.2022

Mathematics

$x_{1}=5+\sqrt{35}$

$x_{2}=5-\sqrt{35}$

Step-by-step explanation:

the equation is

x^2-10x+25=35

to solve we need to make the equation equal to zero, for that we substract 35 on each side:

$x^2-10x+25-35=0\\x^2-10x-10=0$

we have now an equation in the general form: ax^2+bx+c=0

where

a=1

b=-10

c=-10

and we find the values for x with the general formula:

$x=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

substituting known values

$x=\frac{-(-10)+-\sqrt{(-10)^2-4(1)(-10)} }{2(1)}\\x=\frac{10+-\sqrt{100+40} }{2}\\x=\frac{10+-\sqrt{140} }{2}\\x=\frac{10+-\sqrt{4*35} }{2}\\x=\frac{10+-2\sqrt{35} }{2}\\x=5+-\sqrt{35}$

since we had a quadratic equation we will have 2 answers, one taking the positive sign and the other with the negative sign:

$x_{1}=5+\sqrt{35}$ ≈ 10.916

$x_{2}=5-\sqrt{35}$ ≈ -0.916

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