Mathematics: A tourist can bicycle 28 miles in the same time as he can walk 8 miles. If he can ride 10 mph faster than he can walk, how much time (in hr) should he allow to walk a 25-mile trail? (Hint: How fast can he walk?) hr. (enter a fraction)

A tourist can bicycle 28 miles in the same time as

Ответ:

BePaige

29.01.2022

Mathematics

The answer is $\frac{25}{4}$

Step-by-step explanation:

Velocity formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

A tourist can bicycle 28 miles in the same time as he can walk 8 miles. He can ride 10 mph faster than he can walk:

This means that:

$v = \frac{8}{t}$

And

$v + 10 = \frac{28}{t}$

(v + 10)t = 28

From the first equation:

vt = 8

vt + 10 = 28

8 + 10t = 28

10t = 20

$t = \frac{20}{10}$

t = 2

He walks 8 miles in two hours, so:

$v = \frac{8}{2} = 4$

4 miles per hour.

How much time (in hr) should he allow to walk a 25-mile trail?

This is t when d = 25 . So

$v = \frac{d}{t}$

$4 = \frac{25}{t}$

4t = 25

$t = \frac{25}{4}$

The answer is $\frac{25}{4}$

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Ответ:

nnyyy6043

13.08.2021

Mathematics

All you have to do is divide 5 by 865 to see how long they traveled in a day.

865 / 5 = 173

The family drove 173 miles a day.

Hope this helps you! Happy Thanksgiving, here's a turkey!

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A tourist can bicycle 28 miles in the same time as he can walk 8 miles. If he can ride 10 mph faster than he can walk, how much time (in hr) should he allow to walk a 25-mile trail? (Hint: How fast can he walk?) hr. (enter a fraction)

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