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eaglesjohnson414
31.03.2021 •
Mathematics
A vessel without a lid has the shape of a cylinder. The height of the vessel is 1.5 m, and the diameter of the base represents 40% of the height. Determine if 1 kg of paint is enough to completely paint the vessel inside and out, if it is known that for 1 square meter of surface 150g of paint is consumed.
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Ответ:
Yes, 1 kg of paint is enough to completely paint the inside and outside surfaces of the vessel.
Step-by-step explanation:
For the given vessel without a lid,
diameter = 0.4 x 1.5
= 0.6 m
radius =
= ![\frac{0.6}{2}](/tpl/images/1232/0878/1cb30.png)
= 0.3 m
Total external surface area of the vessel = 2
rh + ![\pi](/tpl/images/1232/0878/ad2a1.png)
![r^{2}](/tpl/images/1232/0878/0d015.png)
= [2 x
x 0.3 x 1.5] + [
x
]
= 2.8286 + 0.2829
= 3.1112
Total external surface area of the vessel is 3.1112 square meter.
Total internal and external surface area = 2 x 3.1112
= 6.2224![m^{2}](/tpl/images/1232/0878/ea326.png)
But for 1 square meter, 150 g of paint is consumed. Thus;
for 6.2224
= 6.2224 x 150 g
= 933.36 g
Thus, 6.2224
of area would require 933.36 g of paint.
So that,
Therefore, 1 kg of paint is enough to completely paint the inside and outside surfaces of the vessel.
Ответ:
solve by completing the square.
x2+6x+13=0
move the constant to the right side by subtracting 13 from each side.
x2+6x=−13
divide the coefficient of the x term by 2.
x2+6x=−13
62=3
square the result and add it to both sides.
32=9
x2+6x+9=−13+9
factor the left side and simplify the right side.
(x+3)(x+3)=−4
rewrite as the square of the binomial. note that the 3 in the binomial is the same value 3 that resulted from dividing the coefficient of the x term by 2.
(x+3)2=−4
square root both sides and solve for x.
√(x+3)2=√−4
x+3=±2i
x=−3±2i