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mgkman9814
18.12.2019 •
Mathematics
A20-ft-long wire is used to support a television antaans. the wire is connected to the
antenna 15 ft above the ground. how far away from the base of the tower will the other
end of the wire be located?
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Ответ:
The distance of base of wire to the base of tower is 13.27 ft
Step-by-step explanation:
Given as :
The measure of wire connected between base ad antenna top = 20 ft
The wire is connected to the antenna on tower at height h = 15 ft above the ground
Let The distance of base of wire to the base of tower = x ft
Let the angle drawn on ground = Ф
Now, According to question
In figure AOB
Sin angle =![\dfrac{\textrm perpendicular}{\textrm hypotenuse}](/tpl/images/0424/4631/3ca1a.png)
i.e SinФ =![\dfrac{\textrm AB}{\textrm BO}](/tpl/images/0424/4631/fdd79.png)
Or, SinФ =![\dfrac{\textrm h}{\textrm 20}](/tpl/images/0424/4631/b1646.png)
Or, SinФ =![\dfrac{\textrm 15}{\textrm 20}](/tpl/images/0424/4631/49f83.png)
Or, SinФ =![\dfrac{\textrm 3}{\textrm 4}](/tpl/images/0424/4631/bc1e9.png)
or, Ф =![sin^{-1}(\frac{3}{4})](/tpl/images/0424/4631/a4682.png)
∴ Ф = 48.5°
Now, Again from figure
Tan angle =![\dfrac{\textrm perpendicular}{\textrm base}](/tpl/images/0424/4631/a5d65.png)
i.e TanФ =![\dfrac{\textrm AB}{\textrm OA}](/tpl/images/0424/4631/b7eca.png)
Or, Tan 48.5° =![\dfrac{\textrm h}{\textrm x}](/tpl/images/0424/4631/7aea3.png)
Or, 1.13 =![\dfrac{\textrm 15}{\textrm x}](/tpl/images/0424/4631/0a11e.png)
∴ x =![\dfrac{\textrm 15}{\textrm 1.13}](/tpl/images/0424/4631/d1464.png)
i.e x = 13.27 feet
So, The distance of base of wire to the base of tower = x = 13.27 ft
Hence, The distance of base of wire to the base of tower is 13.27 ft Answer
Ответ: