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mendezmarco2004
22.07.2019 •
Mathematics
A9 cm tall cone shaped paper cup can hold up to 58.9 cm cubed of water. what is the minimum amount of paper needed to make the paper cup, assuming no overlap in the paper? use 3.14 for π.
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Ответ:
r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum
Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2
Therefore, minimum amount of paper required is 92.95 cm^2
Ответ:
$104.738
Step-by-step explanation:
Let's work out the stock plan first:
$2,000 - 7% in the first year = $1,860
$1,860 + 10% = $2,046 in the second year
Savings account:
$2,000 + 3.7% = $2,074 in the first year
$2,074 + 3.7% = $2,150.738 in the second year
The difference:
$2,150.738 - $2,046 = $104.738