Abag contains tiles with the letters p-r-o-b-a-b-i-l-i-t-y. tyler chooses a tile without looking and doesn’t replace it. he chooses a second tile without looking. what is the probability that he will choose the letter i both times?

Sample space = {p, r, o, b, a, b, i, l, I, t, y} = 11 possible outcomes
1sr event: drawing an I ( there are 2 I); P(1st I) = 2/11
2nd event drawing also an i: This is a conditional probability, since one I has already been selected the remaining number of I is now 1, but also the sample space from previously 11 outcome has now 10 outcomes (one letter selected and not replaced)
2nd event : P(also one I) = 1/10
P(selecting one I AND another I) is 2/11 x 1/10

P(selecting one I AND another I) =2/110 = 0.018

649,058,102

=600,000,000 + 40,000,000 + 9,000,000 + 50,000 + 8,000 + 100 + 2