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tiap1011
27.10.2019 •
Mathematics
Abag has 10 yellow poker chips and 4 green poker chips. if you reach in to randomly draw 5 chips, what is the probability of selecting exactly 3 yellow chips and 2 green chips?
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Ответ:
In this problem, the denominator for the probability would be the total number of possibilities. In combination probability, we use the equation: n!/r!(n-r)!, where 'r' is the number of like things out of 'n' objects. So, the denominator would be 5 drawn chips out of a total of 14 chips. So,
denominator = 14!/5!(14-5)! = 2,002 ways
For the numerator, we multiply the combination for 3 out of 10 chips and 2 out of 4 chips.
Numerator = 10!/3!(10-3)! × 4!/2!(4-2)!
Numerator = 720 ways
Thus, the probability is
Probability = 720/2002 = 360/1001 or 35.96%
Ответ:
15 = 75r x 8/365
5475 = 600r
r = 9.125 = 912.5% ≈ 913%