Abag of trail mix weighs 2 lb. by weight, 18% is oats. write a percent proportion that can be used to find the weight of the oats in the trail mix. what is the weight of the oats in the trail mix

since, the total weight of the bag of trail mix = 2 lb

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thus, if 18% of the total trail mix is oats,

then the percentage proportion of the oats in the trail mix =

which is the required proportion.

now, the weight of the oats in the trail mix =

The trail mix total weight, is 2lbs, so, that is the 100%
now, 18% of that is oats
thus 

I am going to use DCVIMS.

I would first distribute the parenthesis.
I would combine like terms.
I would put the variables on both sides.
I would do the inverse.
I would put my final answer.
Then substitute to check if it is correct! :D

6(2x−11)+15=3x+12

Simplify both sides of the equation.

6(2x−11)+15=3x+12

Simplify

6(2x−11)+15=3x+12

(6)(2x)+(6)(−11)+15=3x+12 (Distribute)

12x+−66+15=3x+12

(12x)+(−66+15)=3x+12 (Combine Like Terms)

12x+−51=3x+12

12x−51=3x+12

Subtract 3x from both sides.

12x−51−3x=3x+12−3x

9x−51=12

Add 51 to both sides.

9x−51+51=12+51

9x=63

Divide both sides by 9.

9x / 9 = 63 / 9

x=7

Plug in 7 to the orginal equation to make sure your answer is right!

Hope this helped! :D :D