NateTheBeast12

02.08.2019 • 

Mathematics

Aball is thrown into the air with an upward velocity of 28 ft/s. its height (h) in feet after t seconds is given by the function h=-16t^2+28t+7. how long does it take the ball to reach its maximum height? what is the ball/s maximum height? round to the nearest hundredth, if necessary. a. 1.75 s; 7 ft b. 0.88 s; 43.75 ft c. 0.88 s; 17.5 ft d. 0.88 s; 19.25 ft

Ответ:

mariaaaaa69

15.03.2022

Mathematics

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The Answer is D: 

h = -16t^2 + 28t + 7
h' = -32t + 28

-32t + 28 = 0

-32t = -28 

t = .875 seconds

h(.875) = -16(.875^2) + 28(.875) + 7

h(.875) = 19.25 ft
Rounding time to nearest hundredth gives max at (.88s, 19.25ft)
 

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Ответ:

swaggyd6603

03.09.2020

Mathematics

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Check attached image file.

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