Aball is thrown into the air with an upward velocity of 36 ft/s. its height h in feet after t seconds is given by the function
h=-16t^2+36t+10 in how many seconds does the ball reach its maximum height? round to the nearest hundredth if necessary. what is the ballís maximum height?

H = - 16 t² + 36 t + 10
The maximum height of the ball is at the vertex of the parabola.
t = - b / 2 a
t = -36/-32
t = 1.12 s
The maximum height of the ball:
h max = - 16 * 1.12² + 32* 1.12 + 10 = - 16 * 1.2544 + 35.84 + 10 =
=  - 20.0704 + 45.84 = 25.7696 = 25.77 m

The first step in solving the equation provided is to subtract 3 from 3 itself and 15. You are subtracting three from both sides