Abaseball catcher is performing a stunt for a television commercial. he will catch a baseball (mass 145 g) dropped from a height of 60.0 m above his glove. his glove stops the ball in 0.0100 s. what is the force exerted by his glove on the ball?

174kN

Step-by-step explanation:

F ( force) = mass (m) × acceleration (a)

From equations of motion

h = ut + 1/2at^2

h = 60m, t = 0.01s, u = 0m/s

60 = 1/2×a×0.01^2

a = 60×2/1×10^-4 = 1.2×10^6m/s^2

Mass (m) = 145g = 145/1000 = 0.145kg

F = ma = 0.145×1.2×10^6 = 174000N = 174000/1000 = 174kN

-m - 3n + 12

Step-by-step explanation:

Because we don't know the values of "m" and "n"  the simplest form you can get the equation to be is -m + - 3n + 12

That is because with a negative in front of the parenthesis it's like multiplying by negative 1. So -1 x m, -1 x 3n, and -1 x -12.