Abasketball hoop with a circumference of 56.52, what's the diameter ?

To determine the diameter of the basketball hoop all you have to do is divide the circumference of the hoop, in this case 56.52, by pi. (3.14159 and so on.) The equation playing out as 56.52 * 3.14159. The resulting answer being roughly 17.99 when rounded.

<FCD

<SNP

SN

FC

Look at the vertex of each angle and match it to the other triangle (tri. DFC is congruent to tri. SNP) F=N, which is the vertex, D=S, C=P, DF=SN, and so on