jeremiaht7
06.10.2019 •
Mathematics
Abasketball player has a free throw percentage of 92% . what is the probability she misses at least one of his next 27 free throws?
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Ответ:
89.5%
Step-by-step explanation:
The probability of missing at least one of 27 throws is 1 minus the probability of not missing any throws.
P = 1 − (0.92)^27
P ≈ 0.895
There's about a 89.5% probability that the player misses at least one throw out of 27.
Ответ:
(x, x2 − 3x − 28) for all real numbers
Step-by-step explanation: