ABCD is a quadrilateral with diagonals AC and BD intersecting at P, and AC is perpendicular to BD. also AP = PC = BP =PD

Prove that:
1) AD = AB
2) AC bisects BÂD
3) BÂD = 90°
4) ABCD is a square​

option d

step-by-step explanation:

consider the parent function f(x)=|x|

a)

f(x)=|x|+3

the above function is simply a transformation of vertical shift of 3 units.   hence cannot be wider but has the same width as parent function.

b) f(x) =|x-6|

this function is a transformation of 6 units to the right of the parent functions.hence cannot be wider but has the same width as parent function.

c) f(x)=|x|

this is nothing but the parent funciton itself.

hence cannot be wider but has the same width as parent function.

d) f(x) =9|x|

this is a dilation of the original graph with a scale factor of +9.   hence would be 9 times wider as the parent function.

so option d is the right answer.