Abcd is a rectangle. side ab=2x+4 side ad=4x-2 side dc=3y and side bc=y solve for y and x

perimeter of smaller triangle = 32 m

area of smaller triangle = 80

Step-by-step explanation:

The scale factor is 12/8 = 3/2

The perimeters are in a ratio of 3/2

Let p = perimeter of smaller triangle

So 3/2 = 48/p

3p = 2(48) = 96

p = 32 m

The ratio of the areas is 3^2/2^2 = 9/4

Let a = area of smaller triangle

Then, 9/4 = 180/a

9a = 4(180) = 720

a = 80