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nschavez123
12.07.2019 •
Mathematics
Abee flies at 20 feet per second directly to a flower bed from its hive. hthe bee stays at the flower bed for 15 minutes, then flies directly back to the hive at 12 feet per second. it is away from the hive fore 20 minutes total. a. what equation can you use to find the distance of the flowerbed from the hive? b. how far is the flowerbed from the hive?
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Ответ:
we are given
A bee flies at 20 feet per second directly to a flower bed from its hive
so, forward speed is
flies directly back to the hive at 12 feet per second
so, backward speed is
It is away from the hive fore 20 minutes total
so,
total time = forward time + backward time + stay time
The bee stays at the flower bed for 15 minutes,
20 =tf+tb+15
now, we can change it into seconds
(a)
we know that
distance between hive and flower bed will remain same
Let's assume
forward time =x
so,
we know that
distance = speed*time
now, we can plug values
now, we can plug values
both distances are same
(b)
now, we can solve above equations and find x
add both sides 12x
now, we can find distance
so, distance between hive and flower bed is 2250 feet.........Answer
Ответ:
224
Step-by-step explanation:
in a cylinder the only sides that would actually count is the top and bottomyou would multiply the top and bottom.14 x 16 = 224if I'm wrong let me know