gggggg388
17.09.2019 •
Mathematics
Aboat leaves a dock at 5: 00 pm and travels due south at a speed of 20 km/h. another boat has been heading due east at 15 km/h and reaches the same dock at 6: 00 pm. how many minutes after 5: 00 pm were the two boats closest together? (round your answer to the nearest minute.
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Ответ:
d=√((x2-x1)²+(y2-y1)²)
=√((-15+15t-0)²+(0+20t)²)
=√(225-450t+225t²+400t²)
=√(225-450t+625t²)
Find the derivative
d'= (1/2)(225-450t+625t²)^(-1/2)(-450+1250t)
Set equal to zero and you get
-450+1250t=0
t=450/1250
=0.36 h=22 minutes
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