kelseyduhhh
23.07.2019 •
Mathematics
Aboat leaves a dock at 9: 00 pm and travels due south at a speed of 20 km/h. another boat has been heading due east at 15km/h and reaches the same dock at 10: 00 pm. how many minutes after 9: 00 pm were the two boats closest together? (round your answer to the nearest minute.)
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Ответ:
22 min
Step-by-step explanation:
we need to find the closest distance between two ship.
let us take the ships meet after time t
now distance travel by first ship at any time t is given by 20t
the position of second ship is 15-15t
let us take distance between them is d
therefore
now to get the shortest distance differentiate D w.r.t time
t=0.36hr
thus at
Ответ:
The correct option is 3.
Step-by-step explanation:
From the given figure it is clear that the coordinates of B are (-7,2).
If triangle ABC is reflected over the x-axis, then
After that it rotated 180 degrees,
Then it reflected over the y-axis,
The coordinates of B' are (-7,2).
Therefore, the correct option is 3.