Abowl contains 8 blue marbles and 5 green marbles. elizabeth randomly draws 4 marbles form the bowl. she does not replace the marbles after each draw. what is the probability that she draws 1 blue marble and 3 green marbles?
a. 4/13
b. 13/143
c. 4/143
d. 16/143

Since she puts the marbles back, these events are dependent on each other
so
probability=(desired outcomes)/(total possilbe)
8+5=13=total
probailigy of blue=8/13
gree=5/13
so if she draws theem in that order then
8/13 times (since there is one less, -1 of 13) 5/12 times (assume 1 grreen was drawn from previus drawing) 4/11 times (assume as previus) 3/10

so
8/13 times 5/12 times 4/11 times 3/10=4/143=C

the answer is C 4/143

Given side length "a" and angle "A", calculate the diagonals
p = square root [( 2a^2 - 2a^2 cos(A) )]
q = square root [( 2a^2+ 2a^2 cos(A) )]
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php

side = 36
cos (32) = 0.84805
p = small diagonal =  19.8457652914
q = large diagonal = 69.2108777578