Abox contains 6 red balls and 5 green balls. three balls are selected at random from this box "with replacement". what is the probability that exctly two of the three balls are green?

Given information

Red balls = 6
Green balls = 5


Find total

Total balls = 6 + 5 
Total balls = 11


Find probability 

G = green
R = red
P (R+ G + G) = 6/11 x 5/11 x 5/11 = 150/1331
P (G +R + G) = 5/11 x 6/11 x 5/11 = 150 /1331
P (G +G + R) = 5/11 x 5/11 x 6/11 = 150 /1331
Total probability = 150/1331 +  150 /1331 +  150 /1331 = 450/1331


Ans: The probability is 450/1331

1444km(distance) divided by 110km(scale) = 13.13cm.

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