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papoose10and11
25.07.2019 •
Mathematics
Abox contains 87 coins, only dimes and nickels. the amount of money i the box is $5.45. how many dimes and how many nickels are in the box?
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Ответ:
x+y=87
10x+5y=545
Now solve for y by multiplying the whole of the first equation by the coefficient of x:
10x+10y=870
10x+5y=545
5y=325
y=65 nickels in the box
x+y=87
x=22 dimes in the box
To prove this is correct, we do (10 x 22)+(5 x 65)=545 cents ($5.45)
Ответ:
Ответ:
19 is the answer
Step-by-step explanation:
3x - 4y
= 3 × 5 - 4 × (-1)
= 15 + 4
= 19
hope this answer will help you