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nev322
23.06.2019 •
Mathematics
Acampus survey of owls indicates that 7% are charming, 4% are modest, and 3% are both charming and modest. find the probability that an owl is modest, given that he/she is charming. given that a student isn't modest, what is the probability that they are not charming?
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Ответ:
P(modest | charming) = 0.4286
P(not charming | not modest) = 0.896
Step-by-step explanation:
This is a conditional probability problem.
Let A and B be two dependent events, then:
The probability of A given B is written as:
P (A | B) =![\frac{P(A\ and\ B)}{P(B)}](/tpl/images/0008/7906/3f2c7.png)
So:
The probability that an OWL is modest given that he/she is charming is:
P (modest | charming) =![\frac{P(modest\ and\ charming)} {P(charming)}](/tpl/images/0008/7906/46a26.png)
P (modest | charming) =![\frac{0.03}{0.07}](/tpl/images/0008/7906/bf599.png)
P (modest | charming) = 0.4286
Then, the probability that a student is not modest is:
The probability that a student is not charming and not modest is:
So:
P(not charming | not modest) =![\frac{P(not\ charming\ and\ not\ modest)}{P(not\ modest)}](/tpl/images/0008/7906/1a6c6.png)
P(not charming | not modest) =![\frac{0.92}{0.96}](/tpl/images/0008/7906/04eee.png)
P(not charming | not modest) = 0.9583
Ответ:
4/16 can be divided by 4 to get 1/4
12/18 can be divided by 6 to get 2/3
4/10 can be divided by 2 to get 2/5
16/20 can be divided by 4 to get 4/5