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nixie167
17.07.2019 •
Mathematics
Acar traveling at 47 ft/sec decelerates at a constant 3 feet per second per second. how many feet does the car travel before coming to a complete stop?
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Ответ:
Using the first equation of motion
v=u+a*t
u=47 (initial velocity)
a=-3 (final velocity)
v=0 (Complete stop)
therefore,
→t=( v - u ) / a
t= (0 - (-47) ) / (-3)
t=15.67 second
Now,
Using second equation of motion,
→s=u*t +1/2*a*t²
s=47 * (15.67) + 1/2 * (-3) * (15.67²)
s=736.49 -368.32
Answer= 368.16 feet
Ответ:
Building Snowmen (no skiing) - 10
Skiing - 80
No to building snowmen - 50
Part A:
total of students: 200
140 x
=
200 100
14000 200x
=
200 200
70 = x
70%